Aug 20, 2014
10:05:32am
10:05:32am
Your equation x(x+y)(x+y) isn't the broken down version of x(xy)^2. It is the
broken down version of x(x+y)^2. The broken down version of x(xy)^2 would be x(xy)(xy) which becomes x(x^2y^2) and then x^3y^2.
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- cucciolo25
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