Think order of operations

Aug 20, 2014
10:05:54am

jreid191

x(xy)^2 is equal to x(x^2y^2) since you have to take care of the power first. After that you multiply the x through and end up with x^3y^2

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jreid191

Bio page: jreid191
Joined: Mar 8, 2003
Last login: May 14, 2024
Total posts: 17,119 (658 FO)

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Messages

Author

Time

Algebra Simplification

4n18

8/20/14 9:59am

wolframalpha.com

canadiancougar624

8/20/14 10:01am

There is no +

darkcoug

8/20/14 10:02am

Exactly. It's x times y inside the parentheses, not x + y.

dilbert

8/20/14 10:04am

OHHHHHHHHHHHHHHHHHHHHH

4n18

8/20/14 10:06am

Why are you adding?

workindev

8/20/14 10:04am

Because I am on crack. Thanks!

4n18

8/20/14 10:11am

Breaking it apart gives x * x^2 * y^2 not x(x+y)(x+y). Like darkcoug said, no +

JadoX

8/20/14 10:04am

What is the original equation again?

Iron Coug

8/20/14 10:04am

xy = x * y , not x + y

rggee

8/20/14 10:05am

x * (x * y) * (x * y) = x * x * x * y * y = x^3 * y^2

rggee

8/20/14 10:06am

Thanks! I don't know why I did that.

4n18

8/20/14 10:13am

Your equation x(x+y)(x+y) isn't the broken down version of x(xy)^2. It is the

cucciolo25

8/20/14 10:05am

Note to self: refresh before submitting a response. It's likely been answered.

cucciolo25

8/20/14 10:06am

Think order of operations

jreid191

8/20/14 10:05am

I get 3x-2z.

benny1982

8/20/14 10:10am

Hold on. Still trying to figure it out. Give me another 45 minutes.

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