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Apr 17, 2014
9:48
:50
pm
ColoSpgs
Simplest approach
Use the product of the two denominators as a new common denominator:
2x/(x^2+1) - 1/x^2
2x(x^2)/x^2(x^2+1) - (x^2+1)/x^2(x^2+1) = [2x(x^2) - (x^2+1)]/x^2(x^2+1) = (2x^3-x^2-1)/x^2(x^2+1)
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ColoSpgs
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ColoSpgs
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Messages
Author
Time
help math question here
OU Cougar
4/17/14 9:30pm
wolframalpha.com
canadiancougar624
4/17/14 9:31pm
Ok that site is bad to the bone
OU Cougar
4/17/14 9:41pm
It gives you step-by-step analysis for 5 questions a day
canadiancougar624
4/17/14 9:45pm
Yes, but will it give you sarcasm and funny gifs in response to your questions?
dilbert
4/17/14 9:48pm
by x2 do you mean x^2?
srey
4/17/14 9:31pm
yes
OU Cougar
4/17/14 9:32pm
In order to subtract the two fractions, they have to have the same denominator
dilbert
4/17/14 9:41pm
No wonder I couldn't figure it out
OU Cougar
4/17/14 9:42pm
No, just an engineer spreading the good word of Mathematics
dilbert
4/17/14 9:50pm
Simplest approach
ColoSpgs
4/17/14 9:48pm
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