The first selection affect the odd of the second
Imagine if there were 100 doors and only one had the prize behind it.
If you pick a bad door (which will happen 99/100) then they eliminate all the doors except the good one. So switching once you pick a bad door will always mean you win).
If you pick a good door (which only happens 1/100 times) then they will eliminate all the doors except for a bad one. And switching will mean you always lose when you pick the good door first, but this only happens one out of 100 times.
As long as their are more bad doors than good doors, you always want to switch.